NTA CSIR UGC NET / JRF Exam June 2024 Apply Online Form

Description

Council of Scientific & Industrial Research and National Testing Agency (NTA) has relased CSIR UGC NET / JRF Exam June 2024 Notification. Those candidates who are interested in this CSIR UGC NET June 2024 Exam can apply online from 01 May 2024 to 21 May 2024. Read the notification for NTA CSIR UGC NET Exam, eligibility, Subject Details information, Document Required, age limit, How to Apply and all other information.

Important Dates

• Application Begin : 01/05/2024
• Last Date for Apply Online : 21/05/2024
• Pay Exam Fee Last Date :  22/05/2024
• Correction Date : 25-27 May 2024
• Exam Date : 25-27 June 2024
• Admit Card Available : Before Exam
• Result Declared : Notified Soon

Application Fee

• General / EWS : 1150/-
• OBC : 600/-
• ST / SC : 325/-
• Pay the Examination Fee Through Debit Card / Credit Card / Net Banking / UPI Only.

Age Limit as on 01/06/2024

• Maximum Age : 28 Years for JRF Only.
• Maximum Age : No Limit for Lectureship (LS) / Assistant Professor.

NTA CSIR UGC NET Exam June 2024 Details

Exam Name	CSIR UGC NET Subject Available			NTA CSIR UGC NET Eligibility
NTA CSIR UGC NET Examination June 2024	Chemical Science			M.Sc / Equivalent Degree with 55% Marks for General / OBC Candidates. For SC / ST and PH  Candidates : 50% Marks. Integrated Course and B.E/ B.Tech / B.Pharma and MBBS Candidates Are Also Eligible for CSIR NET 2024.
	Earth, Atmospheric, Ocean and Planetary Science
	Life Science
	Mathematical Science
	Physical Science

Apply Online – Click Here

Official Website – Click Here

Official Notification – Click Here

How to Apply

Step 1: Visit the official website @csirnet.nta.nic.in

Step 2: Click on “Fill online CSIR NET Application Form 2024”

Step 3: If you’re a new applicant, select the “New Registration” option

Step 4: Check the box provided and click “Click Here to Proceed”

Step 5: Enter personal details in the application form

Step 6: Click on checklists and declaration form, then select “Final Submit”

Step 7: Confirm registration by clicking “Yes” in dialogue box displayed on screen

Step 8: Application number will be generated and displayed on screen; click “Complete Application” option

Step 9: Verify mobile number and email address; enter post applied for, centre choice, subject choice etc in new tab

Step 10: Enter security key; click “Submit” button

Step 11: Click “Final Submit” after filling out all required details

Step 12: Upload scanned signature and photograph in the prescribed format.

Step 13: Pay application fees before final submission

Step 14: Download and save the CSIR NET Application Form 2024

Exam Pattern

Particulars	CSIR UGC NET Exam Pattern Highlights
Name of the Exam	Council of Scientific Research National Eligibility Test
Number of papers	5 (Earth Sciences, Life Sciences, Chemical Sciences, Mathematical Sciences and Physical Sciences)
Paper Code	Life Science (703) Mathematical Science (704) Chemical Science (701) Physical Science (705) Earth, Atmospheric, Ocean and Planetary Sciences (702)
Total Questions	Life Science – 75 out of 145
	Mathematical Science – 60 out of 120
	Chemical Science – 75 out of 120
	Physical Science – 55 out of 75
	Earth, Atmospheric, Ocean and Planetary Sciences – 75 out of 150
Exam mode	Online
Exam duration	180 minutes
Type of questions	MCQs
Total marks	200
Marking scheme	Varies as per the subject chosen
Language of paper	English and Hindi